The correct order of the number of unpaired electrons in the given complexes is A [ Fe (…
Chemistry · JEE Main · NTA Exams — Coordination Compounds
The correct order of the number of unpaired electrons in the given complexes is
\(A\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\) \(B\left[\mathrm{FeF}_{6}\right]^{-}\)
\(C\left[\mathrm{CoF}_{6}\right]^{3-}\)
\(\left.D \cdot[C r \text { (oxalate) })_{3}\right]^{3-}\)
\(E \cdot\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\)
Choose the correct answer from the options given below: (Jee Main 2023)
\(A\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\) \(B\left[\mathrm{FeF}_{6}\right]^{-}\)
\(C\left[\mathrm{CoF}_{6}\right]^{3-}\)
\(\left.D \cdot[C r \text { (oxalate) })_{3}\right]^{3-}\)
\(E \cdot\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\)
Choose the correct answer from the options given below: (Jee Main 2023)
- E < A < B < D < C
- A < E < C < B < D
- A < E < D < C < B
- E < A < D < C < B
Answer
(D) E < A < D < C < B
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