An alpha nucleus of energy 1 2 m v^ 2 bombards a heavy nuclear target of charge Ze. Then…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
An alpha nucleus of energy \(\frac{1}{2} m v^{2}\) bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
- v
- \(\frac{1}{m}\)
- \(\frac{1}{\mathrm{v}^{4}}\)
- \(\frac{1}{\mathrm{Ze}}\)
Answer
(B) 1 m
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