The system of simultaneous equations k x+2 y-z=1 [k-1] y-2 z=z (k+2) z=3 have a unique…
Mathematics · JEE Main · NTA Exams — Matrices and Determinants
The system of simultaneous equations
\(k x+2 y-z=1\)
\([k-1] y-2 z=z\)
\((k+2) z=3\)
have a unique solution if k equals
- - 2
- - 1
- 0
- 1
Answer
(C) 0
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