A block of mass m is placed on a surface with a vertical cross section given by y= x^ 3 6…
Physics · NEET · NTA Exams — Laws of Motion
A block of mass m is placed on a surface with a vertical cross section given by \(y=\frac{x^{3}}{6} .\) If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is [JEE (Main) 2014]
- 1/6 m
- 2/3 m
- 1/3 m
- 1/2 m
Answer
(C) 1/3 m
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The minimum velocity (in m/s) with which a car driver must traverse a flat curve of radius 150 m and…
- Conservation of momentum in a collision between particles can be understood from
- A pen of mass ‘ m ’ is lying on a piece of paper of mass M placed on a rough table. If the coefficient of…
- Two carts of masses 200 kg and 300 kg on horizontal rails are pushed apart. Suppose the coefficient of…
- Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving…
- Three forces, P = 10 N, Q = 10 N and R = unknown, are acting on an object which remains under equilibrium…
- A car of mass m is moving on a level circular track of radius R. If µ s represents the static friction…
- A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The…
More Laws of Motion questions · Browse all practice questions