Four identical point masses each equal to m are placed at the corners of a square of side…
Physics · JEE Advanced · NTA Exams — Gravitation
Four identical point masses each equal to m are placed at the corners of a square of side a. The force on a point mass m’ placed at the point of intersection of the two diagonals is:
- \(\frac{4 G \mathrm{~mm}^{2}}{a^{2}}\)
- \(\frac{2 G \mathrm{~mm}^{3}}{a^{2}}\)
- \(\frac{G m m^{\prime}}{a^{2}}\)
- zero
Answer
(D) zero
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