A parallel plate condenser with a dielectric of dielectric constant K between the plates…
Physics · JEE Main · NTA Exams — Electrostatics
A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volts. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is
- \(\frac{1}{2}(\mathrm{~K}-1) \mathrm{CV}^{2}\)
- CV2 (K – 1)/K
- (K – 1) CV2
- zero
Answer
(D) zero
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R)…
- The electric field due to a small dipole at a distance r from its center in axial position is E a . At what…
- A charge 3 C experiences a force of 3000 N when placed in a uniform electric field. The potential difference…
- Given below are two statements. STATEMENT - 1: The surface of a conductor is an equipotential surface…
- A parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the…
- Find the equivalent capacitance between X and Y.
- An electron of 100 eV is fired directly towards a metal plate having surface charge density of –2 × 10 –6 Cm…
- The capacitance (C) for an isolated conducting sphere of radius (a ) is given by 4πε 0 a. This sphere is…
More Electrostatics questions · Browse all practice questions