If ω (≠ 1) is a cube root of unity and (1 + ω) 7 = A + Bω. Then, A + 2B (where A, B ∈ R…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If ω (≠ 1) is a cube root of unity and (1 + ω)7 = A + Bω. Then, A + 2B (where A, B ∈ \(\mathbb{R}\)), equals to
- \(0\)
- \(1\)
- \(3\)
- \(4\)
Answer
(C) 3
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