A ball of mass 'm' which is moving horizontally at a speed 'v' collides with the bob (of…
Physics · JEE Main · NTA Exams — Work, Energy and Power
A ball of mass 'm' which is moving horizontally at a speed 'v' collides with the bob (of mass m) of a pendulum at rest. The collision is perfectly inelastic, the height to which the two balls will rise after the collision is
- \(\frac{\mathrm{v}^{2}}{2 \mathrm{~g}}\)
- \(\frac{v^{2}}{4 g}\)
- \(\frac{v^{2}}{8 g}\)
- \(\frac{v^{2}}{16 g}\)
Answer
(C) v^ 2 8 g
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