‘P’ is a point inside the triangle ABC such that BC ( PA )+ CA ( ~PB )+ AB ( PC )=0 then…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
‘P’ is a point inside the triangle ABC such that \(\mathrm{BC}(\overrightarrow{\mathrm{PA}})+\mathrm{CA}(\overrightarrow{\mathrm{~PB}})+\mathrm{AB}(\overrightarrow{\mathrm{PC}})=0\) then for the triangle ABC the point P is its
- incentre
- circumcentre
- centroid
- orthocentre
Answer
(A) incentre
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