Consider the following two gaseous equilibrium at a definite temperature, AB ( ~g )+ 1 2…
Chemistry · JEE Main · NTA Exams — Equilibrium
Consider the following two gaseous equilibrium at a definite temperature,
- \(\mathrm{AB}(\mathrm{~g})+\frac{1}{2} \mathrm{~B}_{2} \xrightarrow{\mathrm{~K}_{1}} \mathrm{AB}_{2}(\mathrm{~g})\)
- \(2 \mathrm{AB}_{2}(\mathrm{~g}) \xrightarrow{\mathrm{K}_{2}} 2 \mathrm{AB}(\mathrm{~g})+\mathrm{B}_{2}(\mathrm{~g})\)
If K1 and K2 are the equilibrium constants for the reactions (i) and (ii) respectively, then the relation between K1 and K2 is:
- \(K_{1} \cdot K_{2}=1\)
- \(K_{1}^{2}=K_{2}\)
- \(K_{1}^{2} \cdot K_{2}=1\)
- \(K_{1}^{2}=K_{2}(0.5)\)
Answer
(C) K_ 1 ^ 2 K_ 2 =1
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