H 3 C CH = CH 2 + HCl Peroxide Product, the intermediate of reaction is :

Chemistry · JEE Main · NTA Exams — Hydrocarbons

H₃C CH = CH₂ + HCl \(\xrightarrow{\text { Peroxide }}\) Product, the intermediate of reaction is :

1. \(\mathrm{CH}_{3}-\dot{\mathrm{C}} \mathrm{H}-\mathrm{CH}_{3}\)
2. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\dot{\mathrm{C}} \mathrm{H}_{2}\)
3. \(\mathrm{CH}_{3}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}-\mathrm{CH}_{3}\)
4. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}\)

Answer

(C) CH _ 3 - C H - CH _ 3

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• In the following sequence of reactions CH _ 3 CH = CHCH _ 3 O _ 3 ~A [ Zn ] H _ 2 O ~B . The compound B is
• The reagent needed for converting is:
• Major product of the following reaction is - (Jee Main 2024)
• reagent used for the reaction :
• Br ^ * will abstract which of the hydrogen most readily.
• Consider the following compound array l (I) (II) (III) array The relative reactivity towards halonium ion is…
• On heating a mixture of sodium benzoate and sodalime, the following is obtained
• The gas liberated by the electrolysis of dipotassium succinate solution is:

More Hydrocarbons questions · Browse all practice questions