Two particles are executing SHM in a straight line. Amplitude A and time period T of both…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
Two particles are executing SHM in a straight line. Amplitude A and time period T of both the particles are equal. At time t = 0, one particle is at displacement x1 = +A and the other at \(x_{2}=\frac{-A}{2}\) and they are approaching towards each other. After what time they cross each other?
- \(\frac{T}{3}\)
- \(\frac{T}{4}\)
- \(\frac{5 \mathrm{~T}}{6}\)
- \(\frac{\mathrm{T}}{6}\)
Answer
(D) T 6
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