5 sin 2 x + 3 sin x cos x + 6cos 2 x = 5 if (n ∈ I)
Mathematics · JEE Advanced · NTA Exams — Trigonometry
5 sin2 x + \(\sqrt{3}\) sin x cos x + 6cos2x = 5 if (n ∈ I)
- tan x = –1/\(\sqrt{3}\)
- sin x = 0
- x = nπ + π / 2
- x = nπ + π / 6
Answer
(A) tan x = –1/ 3, (C) x = n π + π / 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The number of solution in [0, π/2] of the equation cos 3x tan 5x = sin 7x is
- sin x – cos 2 x – 1 assumes the least value for the set of values of x given by :
- Assertion : The function f (x) = min sin x, cos x takes the value 4 5 twice when x varies from 20 3 to 43 6 …
- A vessel containing water is given a constant acceleration ‘ a ’ towards the right along a straight…
- 2 sin 2 β + 4 cos (α + β) sin α sin β + cos 2 (α + β) =
- The equation k cos x –3 sin x = k + 1 is solvable only if k belongs to the interval
- The principal value of is
- Assertion : The numbers sin 18° and – sin 54° are the roots of same quadratic equation with integer…