The total number of stereoisomers for the complex [Cr(ox) 2 ClBr] 3– (where ox = oxalate)…
Chemistry · JEE Main · NTA Exams — Coordination Compounds
The total number of stereoisomers for the complex [Cr(ox)2ClBr]3– (where ox = oxalate) is:
(Jee Main 2023)
(Jee Main 2023)
- 4
- 3
- 2
- 1
Answer
(B) 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The coordination geometry around the manganese in decacarbonyldimanganese (0) (Jee Main 2024)
- Which of the following is correct order of ligand field strength? (Jee Main 2023)
- Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: Mn…
- Number of complexes from the following with even number of unpaired "d" electrons are____________. [V(H 2 O)…
- The oxidation number of Co in [Co(en) 3 ] 2 (SO 4 ) 3 is
- Which of the following statements is correct regarding the chirality (optical isomerism) of the cis and trans…
- Match List I with List II List I (Coordination complex) List II (Number of unpaired electrons) A. [Cr(CN) 6 ]…
- Match List I with List II: List I (Complexes) List II (Hybridisation) (A) [Ni(CO) 4 ] I. sp 3 (B) [Cu(NH 3 )…
More Coordination Compounds questions · Browse all practice questions