The binding energy per nucleon of deuteron [1 H ^ 2 ] and helium atom (2 He ^ 4 ) is 1.1…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
The binding energy per nucleon of deuteron \(\left[1 \mathrm{H}^{2}\right]\) and helium atom \(\left(2 \mathrm{He}^{4}\right)\) is 1.1 MeV and 7 MeV respectively. If two deuteron atoms react to form a single helium atom, the released energy, is
- 13.9 MeV
- 26.9 MeV
- 23.6 MeV
- 19.2 MeV
Answer
(C) 23.6 MeV
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