Let [ε 0 ] denote of the permittivity of the vacuum, and [μ 0 ] denote the permeability…

Physics · JEE Advanced · NTA ExamsPhysics and Measurement

Let [ε0] denote of the permittivity of the vacuum, and [μ0] denote the permeability of the vacuum. If
M = mass, L = length, T = time and I = electric current, then the dimensional formula of ε0 and μ0 are
  1. [e0] = M–1L–3T2I
  2. [e0] = M–1L–3T4I2
  3. [m0] = MLT–2I–2
  4. [m0] = ML2T–1I

Answer

(B) [ e 0 ] = M –1 L –3 T 4 I 2

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