Let [ε 0 ] denote of the permittivity of the vacuum, and [μ 0 ] denote the permeability…
Physics · JEE Advanced · NTA Exams — Physics and Measurement
Let [ε0] denote of the permittivity of the vacuum, and [μ0] denote the permeability of the vacuum. If
M = mass, L = length, T = time and I = electric current, then the dimensional formula of ε0 and μ0 are
M = mass, L = length, T = time and I = electric current, then the dimensional formula of ε0 and μ0 are
- [
e0] = M–1L–3T2I - [
e0] = M–1L–3T4I2 - [
m0] = MLT–2I–2 - [
m0] = ML2T–1I
Answer
(B) [ e 0 ] = M –1 L –3 T 4 I 2
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