Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of K a as 6.8 ×10 –4 …
Chemistry · Class 11 · CBSE — Equilibrium
Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of Ka as 6.8 ×10–4, 1.8 ×10–4 and 4.8 ×10–9 respectively. What will be the order of their acidic strength?
- HF > HCN > HCOOH
- HF > HCOOH > HCN
- HCN > HF > HCOOH
- HCOOH > HCN > HF
Answer
(B) HF > HCOOH > HCN
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