There are n_ 1 photons of frequency γ 1 in a beam of light. In an equally energetic beam…
Physics · JEE Advanced · NTA Exams — Atoms and Nuclei
There are \(n_{1}\) photons of frequency γ1 in a beam of light. In an equally energetic beam, there are n2 photons of frequency γ2. Then the correct relation is
- \(\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=1\)
- \(\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\frac{\gamma_{1}}{\gamma_{2}}\)
- \(\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\frac{\gamma_{2}}{\gamma_{1}}\)
- \(\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\frac{\gamma_{1}^{2}}{\gamma_{2}^{2}}\)
Answer
(C) n _ 1 n _ 2 = _ 2 _ 1
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