A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and…
Physics · NEET · NTA Exams — Magnetic Effects of Current and Magnetism
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by 60° is W. Now the torque required to keep the magnet in this new position is:
- \(\frac{\sqrt{3 w}}{2}\)
- \(\frac{2 w}{\sqrt{3}}\)
- \(\frac{w}{\sqrt{3}}\)
- \(W \sqrt{3}\)
Answer
(D) W 3
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