Ratio of frequency of revolution of electron in the second excited state of He + and…
Chemistry · JEE Main · NTA Exams — Atomic Structure
Ratio of frequency of revolution of electron in the second excited state of He+ and second state of hydrogen is
- \(\frac{32}{27}\)
- \(\frac{27}{32}\)
- \(\frac{1}{54}\)
- \(\frac{27}{2}\)
Answer
(A) 32 27
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