If θ = sin –1 x + cos –1 x – tan –1 x, x ≥ 0, then the smallest interval in which θ lies…
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If θ = sin–1 x + cos–1 x – tan–1 x, x ≥ 0, then the smallest interval in which θ lies, is given by :
- \(\frac{\pi}{2} \leq \theta \leq \frac{3 \pi}{4}\)
- \(-\frac{\pi}{4} \leq \theta \leq 0\)
- \(0 \leq \theta \leq \frac{\pi}{4}\)
- \(\frac{\pi}{4} \leq \theta \leq \frac{\pi}{2}\)
Answer
(D) 4 2
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