A bird is flying in air at a height of X cm. It observes a fish vertically below it, at a…
Physics · NEET · NTA Exams — Optics
A bird is flying in air at a height of X cm. It observes a fish vertically below it, at a depth of Y cm from the surface of water. If μ is the refractive index of water, the distance (vertical) of the fish as observed by the bird is
- \(x+\frac{Y}{\mu}\)
- \(X+Y\)
- \(\mu X+Y\)
- \(\mu(X+Y)\)
Answer
(A) x+ Y
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