Find the cross product of the following vectors: A =2 i +3 j +8 k and E = i -2 j +6 k
Physics · NEET · NTA Exams — BASIC MATHEMATICS AND VECTOR
Find the cross product of the following vectors:
\(\overrightarrow{\mathrm{A}}=2 \hat{i}+3 \hat{j}+8 \hat{k}\) and \(\vec{E}=\hat{i}-2 \hat{j}+6 \hat{k}\)
- \(2 \hat{i}+4 \hat{j}-7 \hat{k}\)
- \(34 \hat{i}-4 \hat{j}-7 \hat{k}\)
- \(24 \hat{i}+4 \hat{j}\)
- \(2 \hat{i}-4 \hat{j}-7 \hat{k}\)
Answer
(B) 34 i -4 j -7 k
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