The correct order of energies of molecular orbitals of N 2 molecule is:

The correct order of energies of molecular orbitals of N₂ molecule is:

\(\begin{array}{l} \sigma 15<\sigma^{*} 15<\sigma 25<\sigma^{*} 25<\left(\pi 2 p_{x}=\pi 2 p_{y}\right) \\ <\left(\pi^{*} 2 p_{x}=\pi^{*} 2 p_{y}\right)<\sigma 2 p_{z}<\sigma^{*} 2 p_{z} \end{array}\)
\(\begin{array}{l} \sigma 15<\sigma^{*} 15<\sigma 25<\sigma^{*} 25<\left(\pi 2 p_{x}=\pi 2 p_{y}\right) \\ <\sigma 2 p_{z}<\left(\pi^{*} 2 p_{x}=\pi^{*} 2 p_{y}\right)<\sigma^{*} 2 p_{z} \end{array}\)
\(\begin{array}{l} \sigma 15<\sigma^{*} 15<\sigma 25<\sigma^{*} 25<\sigma 2 p_{2}< \\ \left(\pi 2 p_{x}=\pi 2 p_{y}\right)<\left(\pi^{*} 2 p_{x}=\pi^{*} 2 p_{y}\right)<\sigma^{*} 2 p_{z} \end{array}\)
\(\begin{array}{l} \sigma 15<\sigma^{*} 15<\sigma 25<\sigma^{*} 25<\sigma 2 p_{\mathrm{z}}< \\ \sigma^{*} 2 p_{\mathrm{z}}<\left(\pi 2 p_{\mathrm{z}}=\pi 2 p_{\mathrm{y}}\right)<\left(\pi^{*} 2 p_{\mathrm{z}}=\pi^{*} 2 p_{\mathrm{y}}\right) \end{array}\)

Answer

(B) array l 15< ^ * 15< 25< ^ * 25< ( 2 p_ x = 2 p_ y ) < 2 p_ z < ( ^ * 2 p_ x = ^ * 2 p_ y )< ^ * 2 p_ z array

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