The magnetic flux through a loop of resistance 10 Ω is given by = [5 t^ 2 -4 t+1 ] Wb …
Physics · NEET · NTA Exams — Electromagnetic Induction and Alternating Currents
The magnetic flux through a loop of resistance 10 Ω is given by \(\Phi=\left[5 t^{2}-4 t+1\right] \mathrm{Wb}\). How much current is induced in the loop after 0.2 s?
- 0.4 A
- 0.2 A
- 0.04 A
- 0.02 A
Answer
(B) 0.2 A
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