From the top of a tower, a particle is thrown vertically downwards with a velocity of 10…
Physics · JEE Main · NTA Exams — Kinematics
From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take g = 10 m/s2)
- 5 : 7
- 7 : 5
- 3 : 6
- 6 : 3
Answer
(B) 7 : 5
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