A constant horizontal force F is applied on the top of a solid sphere and a hollow sphere…
Physics · JEE Advanced · NTA Exams — Rotational Motion
A constant horizontal force F is applied on the top of a solid sphere and a hollow sphere of same mass and radius both kept on a sufficiently rough surface. Let a1 and a2 be their linear accelerations then:
- a1 = a2
- a1 > a2
- a1 < a2
- data sufficient
Answer
(B) a1 > a2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A sphere S rolls without slipping, moving with a constant speed on a plank P. The friction between the upper…
- A small ball of mass m suspended from the ceiling at a point O by thread of length l moves along a horizontal…
- A smooth table is placed horizontally and an ideal spring of spring constant k = 1000 N/m and unextended…
- A body of mass 2 kg is tied at one end of a string 1 m long. The other end is fixed and the body revolves in…
- A conical pendulum consists of a mass M suspended from a strong string of length l . The mass executes a…
- A motorcyclist wants to drive on the vertical surface of wooden ‘well’ or radius 5 m, with a minimum speed of…
- A mass of 2 kg is whirled in a horizontal circle by means of a string at an initial speed of 5 rpm. Keeping…
- A particle performs uniform circular motion with an angular momentum L. If the frequency of particle’s motion…
More Rotational Motion questions · Browse all practice questions