In Young's double-slit experiment, the distance between two slits is d = 1 mm. Two light…

Physics · JEE Main · NTA ExamsOptics

In Young's double-slit experiment, the distance between two slits is d = 1 mm. Two light waves of wavelength \(\lambda_{1}=500 \mathrm{~nm}\) and \(\lambda_{2}=700 \mathrm{~nm}\), respectively are incident on the slits, the least distance from the central maxima where the bright fringes due to both the wavelengths coincide for the first time is [given, distance between the slits and the screen is 0.8 m]
  1. \(2.5 \mathrm{~mm}\)
  2. \(4.9 \mathrm{~mm}\)
  3. \(3.5 \mathrm{~mm}\)
  4. \(2.8 \mathrm{~mm}\)

Answer

(D) 2.8 ~mm

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