A reduction B CHCl _ 3 / KOH C reduction N-methylaniline, then A is
Chemistry · JEE Main · NTA Exams — Organic Compounds Containing Nitrogen
\(\mathrm{A} \xrightarrow{\text { reduction }} \mathrm{B} \xrightarrow{\mathrm{CHCl}_{3} / \mathrm{KOH}} \mathrm{C} \xrightarrow{\text { reduction }}\) N-methylaniline, then A is
- \(\mathrm{CH}_{3} \mathrm{NH}_{2}\)
Answer
(B)
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