In Young’s double-slit experiment setup with light of wavelength λ = 6000 Å, distance…
Physics · JEE Advanced · NTA Exams — Optics
In Young’s double-slit experiment setup with light of wavelength λ = 6000 Å, distance between the two slits is 2 mm and distance between the plane of slits and the screen in 2 m. The slits are of equal intensity. When a sheet of glass of refractive index 1.5 (which permits only a fraction of the incident light to pass through) and thickness 8000 Å is placed in front of the lower slit, it is observed that the intensity at a point P, 0.15 mm above the central maxima, does not change.
The phase difference at point P without inserting the slab is
- \(\frac{3 \pi}{4}\)
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{2}\)
- \(\frac{\pi}{3}\)
Answer
(C) 2
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