Consider two rods of same length and different specific heats (s 1 , s 2 ), thermal…
Physics · NEET · NTA Exams — Properties of Solids and Liquids
Consider two rods of same length and different specific heats (s1, s2), thermal conductivities (k1, k2) and areas of cross-section (A1, A2) and both having temperatures (T1, T2) at their ends. If their rate of loss of heat due to conduction is equal, then :
- \(k_{1} A_{1}=k_{2} A_{2}\)
- \(\frac{k_{1} A_{1}}{5_{1}}=\frac{k_{2} A_{2}}{5_{2}}\)
- \(k_{2} A_{1}=k_{1} A_{2}\)
- \(\frac{k_{2} A_{1}}{5_{2}}=\frac{k_{1} A_{2}}{5_{1}}\)
Answer
(A) k_ 1 A_ 1 =k_ 2 A_ 2
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