Two springs having spring constant of k 1 = 25 N/m and k 2 = 16 N/m are stretched by…
Physics · NEET · NTA Exams — Work, Energy and Power
Two springs having spring constant of k1 = 25 N/m and k2 = 16 N/m are stretched by forces F1 and F2 to have equal potential energy. The ratio of F1 / F2 is
- \(\frac{3}{4}\)
- \(\frac{4}{5}\)
- \(\frac{5}{4}\)
- \(\frac{7}{4}\)
Answer
(C) 5 4
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