The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a 0 is…
Chemistry · JEE Advanced · NTA Exams — Atomic Structure
The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0 is Bohr radius] (2013)
- \(\frac{\mathrm{h}^{2}}{4 \pi^{2} \mathrm{ma}_{0}^{2}}\)
- \(\frac{\mathrm{h}^{2}}{16 \pi^{2} \mathrm{ma}_{0}^{2}}\)
- \(\frac{\mathrm{h}^{2}}{32 \pi^{2} \mathrm{ma}_{0}^{2}}\)
- \(\frac{\mathrm{h}^{2}}{64 \pi^{2} \mathrm{ma}_{0}^{2}}\)
Answer
(C) h ^ 2 32 ^ 2 ma _ 0 ^ 2
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