The Henry’s law constant for the solubility of N 2 gas in water at 298 K is 1.0 × 10 5…
Chemistry · JEE Advanced · NTA Exams — Solutions
The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 105 atm. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
- 4.0 × 10–4
- 4.0 × 10–5
- 5.0 × 10–4
- 4.0 × 10–6
Answer
(A) 4.0 × 10 –4
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