d y d x = x y x^ 2 +y^ 2 ; y(1)=1 then a value of x satisfying y(x) = e is :

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\sqrt{3} e\)
2. \(\frac{\mathrm{e}}{\sqrt{2}}\)
3. \(\sqrt{2} e\)
4. \(\frac{1}{2} \sqrt{3} \mathrm{e}\)

Answer

(C) 2 e

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