If the distance of the point P (1, –2, 1) from the plane x + 2 y – 2 z = α , where α > 0…
Mathematics · JEE Advanced · NTA Exams — Three Dimensional Geometry
If the distance of the point P(1, –2, 1) from the plane
x + 2y – 2z = α, where α > 0, is 5, then the foot of the perpendicular from P to the plane is
x + 2y – 2z = α, where α > 0, is 5, then the foot of the perpendicular from P to the plane is
Answer
(A)
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