A force F =-k( y +x j ) (where k is a positive constant) acts on a particle moving in the…
Physics · JEE Main · NTA Exams — Work, Energy and Power
A force \(\vec{F}=-k(\hat{y}+x \hat{j})\) (where k is a positive constant) acts on a particle moving in the X-Y plane. Starting from the origin, the particle is taken along the positive X-axis to the point (a, 0) and then parallel to the Y-axis to the point (a, a). The total work done by the force F on the particle is
- \(\text { — }\)2ka2
- 2ka2
- \(\text { — }\)ka2
- ka2
Answer
(C) — ka 2
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