The reaction of K 3 [Fe(CN) 6 ] with freshly prepared FeSO 4 solution produces a dark…

Chemistry · JEE Advanced · NTA Exams — d- and f-Block Elements


The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull’s blue. Reaction of K4 [Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of (2021)
  1. \(\left[\mathrm{Fe}(\mathrm{NO})_{2}\left(\mathrm{SO}_{4}\right)_{2}\right]^{2-}\)
  2. \(\left[\mathrm{Fe}(\mathrm{NO})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{3+}\)
  3. \(\left[\mathrm{Fe}(\mathrm{NO})_{4}\left(\mathrm{SO}_{4}\right)_{2}\right]\)
  4. \(\left[\mathrm{Fe}(\mathrm{NO})\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\right]^{2+}\)

Answer

(D) [ Fe ( NO ) ( H _ 2 O )_ 5 ]^ 2+

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