The work done by a force F = (-6 x^ 3 i ) N is displacing a particle from x = 4 m to x =…
Physics · JEE Main · NTA Exams — Work, Energy and Power
The work done by a force \(\bar{F}=\left(-6 x^{3} \hat{i}\right)\) N is displacing a particle from x = 4 m to x = –2 m is
- – 240 J
- 360 J
- 420 J
- will depend upon the path
Answer
(B) 360 J
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