Two adjacent sides of a parallelogram ABCD are given by A B =2 i +10 j +11 k and A D =- i…
Mathematics · JEE Advanced · NTA Exams — Vector Algebra
Two adjacent sides of a parallelogram ABCD are given by \(\overrightarrow{A B}=2 \hat{\mathbf{i}}+10 \hat{\mathbf{j}}+11 \hat{\mathbf{k}}\) and \(\overrightarrow{A D}=-\hat{i}+2 \hat{j}+2 \hat{k} .\)
The side AD is rotated by an acute angle α in the plane of the parallelogram so that AD becomes AD′. If AD′ makes a right angle with the side AB, then the cosine of the angle α is given by
The side AD is rotated by an acute angle α in the plane of the parallelogram so that AD becomes AD′. If AD′ makes a right angle with the side AB, then the cosine of the angle α is given by
Answer
(B)
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