The cell, Zn | Zn 2+ (1M) || Cu 2+ (1M) | Cu (Eº cell = 1.10V) was allowed to be…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
The cell, Zn | Zn2+ (1M) || Cu2+ (1M) | Cu (Eºcell = 1.10V) was allowed to be completely discharged at 298 K. The relative concentration of Zn2+ to Cu2+, i.e., \(\left(\frac{\left[\boxtimes^{2+}\right]}{\left[\mathbb{U}^{2+}\right]}\right)\)is
- 9.65 × 104
- antilog (24.08)
- 37.3
- 1037.3
Answer
(D) 10 37.3
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