The focal length of a mirror is given by 1 f = 1 u + 1 v where u and v represent object…
Physics · JEE Advanced · NTA Exams — Physics and Measurement
The focal length of a mirror is given by \(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\) where u and v represent object and image distances respectively. The maximum relative error in f is
- \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}\)
- \(\frac{\Delta f}{f}=\frac{1}{\Delta u / u}+\frac{1}{\Delta v / v}\)
- \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}-\frac{\Delta(u+v)}{u+v}\)
- \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}+\frac{\Delta u}{u+v}+\frac{\Delta v}{u+v}\)
Answer
(D) f f = u u + v v + u u+v + v u+v
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