The number of iodine atoms present in 50 mL of a 0.1M KI solution is:

Chemistry · JEE Main · NTA ExamsSome Basic Concepts in Chemistry

The number of iodine atoms present in 50 mL of a 0.1M KI solution is:
  1. \(12.0 \times 10^{23}\)
  2. \(6.0 \times 10^{22}\)
  3. \(3.0 \times 10^{21}\)
  4. \(6.0 \times 10^{23}\)

Answer

(C) 3.0 10^ 21

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Some Basic Concepts in Chemistry questions · Browse all practice questions