The number of iodine atoms present in 50 mL of a 0.1M KI solution is:
Chemistry · JEE Main · NTA Exams — Some Basic Concepts in Chemistry
The number of iodine atoms present in 50 mL of a 0.1M KI solution is:
- \(12.0 \times 10^{23}\)
- \(6.0 \times 10^{22}\)
- \(3.0 \times 10^{21}\)
- \(6.0 \times 10^{23}\)
Answer
(C) 3.0 10^ 21
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