If _ r=1 ^ 25 ^ 54 c_ r ^ 54-r c_ 25-r =k ( ^ 54 c_ 25 ) , then K is equal to:
Mathematics · JEE Main · NTA Exams — Permutations and Combinations
If \(\sum_{r=1}^{25}\left\{{ }^{54} c_{r}{ }^{54-r} c_{25-r}\right\}=k\left({ }^{54} c_{25}\right)\), then K is equal to:
- 224
- 225-1
- 225
- (25)2
Answer
(C) 2 25
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