Two objects having the same mass m, are tied at the ends of a light string of length 2a…
Physics · NEET · NTA Exams — Laws of Motion
Two objects having the same mass m, are tied at the ends of a light string of length 2a. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance, a from the centre P. Now, the mid–point of the string is pulled vertically upwards with a small but constant force F. As a result, the objects move towards each other on the surface. The magnitude of acceleration, when the separation between them becomes 2x is
- \(\frac{F}{2 m} \frac{a}{\sqrt{a^{2}-x^{2}}}\).
- \(\frac{F}{2 m} \frac{x}{\sqrt{a^{2}-x^{2}}}\).
- \(\frac{F}{2 m} \frac{x}{a}\).
- \(\frac{F}{2 m} \frac{\sqrt{a^{2}-x^{2}}}{x}\).
Answer
(B) F 2 m x a^ 2 -x^ 2 .
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