The total number of terms in the expansion of (a + b + c + d) n , n N is
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
The total number of terms in the expansion of
(a + b + c + d)n, n \(\in\) N is
(a + b + c + d)n, n \(\in\) N is
- \(\frac{\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)}{6}\)
- \(\frac{\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)(\mathrm{n}+3)}{6}\)
- \(\frac{(\mathrm{n}+1)(\mathrm{n}+2)(\mathrm{n}+3)}{6}\)
- none of these
Answer
(C) ( n +1)( n +2)( n +3) 6
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