An organic compound C 4 H 8 O, is found to be optically active. Which of the following…
Chemistry · JEE Main · NTA Exams — Some Basic Principles of Organic Chemistry
An organic compound C4H8O, is found to be optically active. Which of the following could it be ?
- CH3 –– CH2 –– CH2 –– CHO
- CH3 –– CO –– CH2 –– CH3
- \(\mathrm{CH}_{2}=\mathrm{CH}-\stackrel{*}{\mathrm{C}} \mathrm{H}(\mathrm{OH})-\mathrm{CH}_{3}\)
- (CH3)2CH –– CHO
Answer
(C) CH _ 2 = CH - * C H ( OH )- CH _ 3
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