The electric field part of an electromagnetic wave in vacuum is E = 3.1 N C ^ -1 [(1.8…
Physics · Class 12 · CBSE — Electromagnetic Waves
The electric field part of an electromagnetic wave in vacuum is \(E = 3.1 \text{ N C}^{-1} \cos\!\left[(1.8 \text{ rad m}^{-1})\,y + (5.4 \times 10^{8} \text{ rad s}^{-1})\,t\right]\). The wavelength of this electromagnetic wave is
- 1.5 m
- 2 m
- 2.5 m
- 3.5 m
Answer
(D) 3.5 m
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