Number of moles of K 2 Cr 2 O 7 reduced by one mole of Sn 2+ ions is
Chemistry · JEE Main · NTA Exams — d- and f-Block Elements
Number of moles of K2Cr2O7 reduced by one mole of Sn2+ ions is
- \(\frac{1}{3}\)
- 3
- \(\frac{1}{6}\)
- 6
Answer
(A) 1 3
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