For the reaction A + E product doubling the initial concentration of both the reactants…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
For the reaction \(\mathrm{A}+\mathrm{E} \longrightarrow \text { product }\) doubling the initial concentration of both the reactants increases the rate by a factor of 8 and doubling the concentration of B alone doubles the rate. The rate law for the reaction is:
- \(r=K[A][B]^{2}\)
- \(r=K[A]^{2}[B]\)
- \(\mathrm{r}=\mathrm{K}[\mathrm{~A}][\mathrm{B}]\)
- \(\mathrm{r}=\mathrm{K}[\mathrm{G}]\)
Answer
(B) r=K[A]^ 2 [B]
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